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JEE MATHEMATICS MCQ: COMBINATIONS

1 Easy
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Application +4 | -1
∑r=0n(r+3r+1)ncr=7⋅(210)−210\sum\limits_{r=0}^{n}{\left( \frac{r+3}{r+1} \right)} n_{c_r}=\frac{7 \cdot\left(2^{10}\right)-2}{10} then n=n=
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Correct option: D
9
Option D (9) is correct because by simplifying the summation and comparing it to the given expression, we can solve for n.

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