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NEET UG PHYSICS MCQ: CURRENT ELECTRICITY

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Application +4 | -1
An electron beam has an aperture 1.0 mm21.0 \mathrm{~mm}^2. A total of 6×10166 \times 10^{16} electrons go through any perpendicular cross section per second. Find the current density in the beam. (in A/m2\mathrm{A} / \mathrm{m}^2 )
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Correct option: B
9.6×1039.6 \times 10^3
Option B (9.6×103A/m29.6 \times 10^3 \mathrm{A} / \mathrm{m}^2) is correct because it is calculated by dividing the total current by the area of the aperture.

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