The domain of the function $\cos ^{-1}(2 x-1)$ is

JEE MATHEMATICS MCQ: FUNCTIONS

1 Medium

1 of 1

Understanding +4 | -1

The domain of the function

\cos ^{-1}(2 x-1)

View answer and explanation

Correct option: A

[0,1]

Option A ([0,1]) is correct because the domain of arccos(x) is [-1,1], so -1 <= 2x-1 <= 1 which implies 0 <= x <= 1.

Practice All Chapter MCQs →

f:(-\infty, 2] \longrightarrow(-\infty, 4]

f(x)=x(4-x)

f^{-1}(x)

g(f(x))=|\sin x|

f(g(x))=(\sin \sqrt{x})^2

f:\left( {2,\;3} \right) \to \left( {0,\;1} \right)

f\left( x \right) = x - \left[ x \right]

{f^{ - 1}}\left( x \right)

f: R \rightarrow R

f(x)=x^4

f(x)=(x+1)^2-1(x \geq-1)

S=\left\{x: f(x)=f^{-1}(x)\right\}