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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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If 1+λ+λ2+...+λn=(1+λ)(1+λ2)(1+λ4)(1+λ8)(1+λ16),1 + \lambda + {\lambda ^2} + ... + {\lambda ^n} = \left( {1 + \lambda } \right)\left( {1 + {\lambda ^2}} \right)\left( {1 + {\lambda ^4}} \right)\left( {1 + {\lambda ^8}} \right)\left( {1 + {\lambda ^{16}}} \right), then the value of nn is (where n∈N)n \in N)
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Correct option: C
31
Option C (31) is correct because by equating the LHS and RHS after simplification, we find that n = 31.

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