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NEET UG CHEMISTRY MCQ: ALDEHYDES & KETONES & CARBOXYLIC ACIDS

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Application +4 | -1
Product (Y) of the given reaction is
CH3CH2COOHβ†’Β (ii)Β H2OΒ (i)Β Cl2/Red PXβ†’Β Alc.Β KOHY\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{COOH} \xrightarrow[\text { (ii) } \mathrm{H}_2 \mathrm{O}]{\text { (i) } \mathrm{Cl}_2 / \mathrm{Red} \,\mathrm{P}} \mathrm{X} \xrightarrow{\text { Alc. } \mathrm{KOH}} \mathrm{Y}
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Correct option: C
CH2=CHCOOH{\text{C}}{{\text{H}}_2} = {\text{CHCOOH}}
Option C (CH2=CHCOOH{\text{C}}{{\text{H}}_{\text{2}}} = {\text{CHCOOH}}) is correct because the reaction sequence involves alpha-halogenation followed by dehydrohalogenation to form an alpha, beta-unsaturated acid.

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