JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

1 Easy

1 of 1

Application +4 | -1

The area bounded by the

x

-axis, the curve

y=f(x)

and the lines

x=1, x=b

is equal to

\sqrt{b^2+1}-\sqrt{2}

for all

b>1

, then

f(x)

, is

View answer and explanation

Correct option: D

x / \sqrt{x^2+1}

Option D (

x / \sqrt{x^2+1}

) is correct because it is obtained by differentiating the given equation with respect to

b

using the Fundamental Theorem of Calculus.

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