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JEE MATHEMATICS MCQ: STATISTICS

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Application +4 | -1
Let the mean and the variance of 5 observations x1x_1, x2,x3,x4,x5x_2, x_3, x_4, x_5 be 245\frac{24}{5} and 19425\frac{194}{25} respectively. If the mean and variance of the first 4 observation are 72\frac{7}{2} and a respectively, then (4a+x5)\left(4 a+x_5\right) is equal to
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Correct option: B
15
Option B (15) is correct because it is the value obtained by using the given mean and variance to find the missing value and then calculating 4a + x_5.

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