JEE MATHEMATICS MCQ: LIMITS

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Analyzing +4 | -1

f(x)=\lim \limits_{{n \rightarrow \infty}} \frac{1}{\left(\frac{3}{\pi} \tan ^{-1} 2 x\right)^{2 n}+5}

, then the set of values of

x

for which

f(x)=0

, is

View answer and explanation

Correct option: A

|2 x|>\sqrt{3}

Option A (

|2x| > \sqrt{3}

) is correct because the function f(x) equals zero if and only if

(\frac{3}{\pi} \tan^{-1} 2x)^2 > 1

, leading to

|2x| > \sqrt{3}

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