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JEE CHEMISTRY MCQ: CHEMICAL BONDING & MOLECULAR STRUCTURE
1
Hard
1 of 1
Analyzing
+4 | -1
Statement-1: is more stable than the , and is also more stable than the .
Statement-2: formed when has lost an anti-bonding electron, and formed when has lost N.B.M.O. having anti-bonding character.
Statement-2: formed when has lost an anti-bonding electron, and formed when has lost N.B.M.O. having anti-bonding character.
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Correct option: A
Statement-1 is true, statement-2 is true and statement- 2 is correct explanation for statement-1.
Option A (Statement-1 is true, statement-2 is true and statement- 2 is correct explanation for statement-1) is correct because and are more stable due to the removal of an antibonding electron from NO and a non-bonding molecular orbital electron having antibonding character from CO, respectively.
More Questions from CHEMICAL BONDING & MOLECULAR STRUCTURE
Practice All Chapter MCQs β
The hybridization in sulphur dioxide is
has the same geometry as:
The pair of molecules forming strongest hydrogen bonds are
Paramagnetism is shown by
Which statement is correct?
Assertion (A) : is a weaker Lewis acid than .
Reason (R) : The planar molecule is stabilised to a greater extent than by -bonding.
Reason (R) : The planar molecule is stabilised to a greater extent than by -bonding.
