JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

1 Easy

1 of 1

Application +4 | -1

The sum of the series

\frac{1}{{\sqrt 1 + \sqrt 2 }} + \frac{1}{{\sqrt 2 + \sqrt 3 }} + \frac{1}{{\sqrt 3 + \sqrt 4 }} + \ldots + \frac{1}{{\sqrt {{n^2} - 1} + \sqrt {{n^2}} }}

equals

View answer and explanation

Correct option: D

n - 1

Option D (

n - 1

) is correct because the series telescopes, leaving only the last term's square root minus the first term's square root.

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