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JEE MATHEMATICS MCQ: PERMUTATIONS

1 Easy

1 of 1

Application +4 | -1

Let

{P_m}

stand for

{\;^m}{P_m}.

Then,

1 + {P_1} + 2\;{P_2} + 3\;{P_3} + \ldots + n.{P_n}

is equal to

View answer and explanation

Correct option: C

\left( {n + 1} \right)\;! - 1

Option C (

\left( {n + 1} \right)\,! - 1

) is correct because it represents the sum of the series

1 + {P_1} + 2\;{P_2} + 3\;{P_3} + \ldots + n.{P_n}

.

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