JEE PHYSICS MCQ: WAVES

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Application +4 | -1

The pressure wave

p = 0.01\sin \left[ {1000t - 3x} \right]N{m^{ - 2}},\,

corresponds to the sound produced by a vibrating blade on a day when atmospheric temperature is

0^\circ C

. On some other day when temperature is

T

, the speed of sound produced by the same blade and at the same frequency is found to be

336\;m{s^{ - 1}}

. Approximate value of

T

View answer and explanation

Correct option: D

4^\circ C

Option D (

4^{\circ} C

) is correct because the temperature is calculated using the relationship between the speed of sound and temperature.

More Questions from WAVES

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3\,\,kHz

0.5

f\mathrm{ }Hz

V\mathrm{ }m/sec

0.2\,\,V

y = \frac{3}{{{{\left( {2x + 3t} \right)}^2} + 4}},

(– \mathrm{ve}) \,x

y = f(kx +\omega t),

X

0.01\,\,s

5 \mathrm{~m}

245 \mathrm{~g}

1 \mathrm{~kg}

g=980 \mathrm{~cm} \mathrm{~s}^{-2}

T

V