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JEE PHYSICS MCQ: MOTION IN A STRAIGHT LINE

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Application +4 | -1
If initial velocity of a body is u⃗=2i^−2j^+3k^\vec u = 2\hat i - 2\hat j + 3\hat k and is changed to v⃗=2i^−4j^+5k^\vec v = 2\hat i - 4\hat j + 5\hat k in a time of 10sec. Its accelerated vector is
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Correct option: D
−j^+k^5\frac{{ - \hat j + \hat k}}{5}
Option D (−j^+k^5\frac{{ - \hat j + \hat k}}{5}) is correct because the acceleration vector is calculated by finding the change in velocity over time.

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