JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Application +4 | -1

\mathrm{S}_n

for the series

\left(1^2-2^2\right)+\left(3^2-4^2\right)+\left(5^2-6^2\right)+\ldots

View answer and explanation

Correct option: C

-n(2 n+1)

Option C (-n(2n+1)) is correct because it is the correct sum of the given series up to n terms.

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\frac{3}{4}