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NEET UG CHEMISTRY MCQ: STRUCTURE OF ATOM

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Application +4 | -1
Bohr’s radius of 2nd orbit of Be3+\mathrm{B}{\mathrm{e}^{3 + }} is equal to that of
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Correct option: D
First orbit of hydrogen
Option D (First orbit of hydrogen) is correct because the radius of the nth orbit is given by r=a0n2Zr = a_0 \frac{n^2}{Z}, where a0a_0 is the Bohr radius, n is the orbit number, and Z is the atomic number. Setting the radii equal allows solving for the equivalent orbit.

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