NEET UG PHYSICS MCQ: SEMI CONDUCTOR DEVICES

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Analyzing +4 | -1

A semi conductor has an electron concentration of

8 \times 10^{13}

per

\mathrm{cm}^3

and a hole concentration of

5 \times 10^{12}

per

\mathrm{cm}^3

. The electron mobility is

25000 \mathrm{~cm}^2 \mathrm{~V}^{-1} \mathrm{~s}^{-1}

and the hole mobility is

100 \mathrm{~cm}^2 \mathrm{~V}^{-1} \mathrm{~s}^{-1}

. Then,

View answer and explanation

Correct option: A

The semiconductor is n-type.

Option A (The semiconductor is n-type) is correct because the electron concentration is significantly higher than the hole concentration.

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I = A{T^2}{e^{q/{V_L}}}

{V_L}

\sqrt{n}.

n

p - n\;

{10^{17}}\mathrm{c}{\mathrm{m}^{ - 3}}

P

{10^{16}}

\mathrm{c}{\mathrm{m}^{ - 3}}

N

kT =

{n_i} = 1.4 \times {10^{10}}

\mathrm{c}{\mathrm{m}^{ - 3}}