JEE MATHEMATICS MCQ: SYSTEM OF CIRCLES

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Application +4 | -1

The equation of the common tangent of the two touching circles,

{y^2} + {x^2} - 6x - 12y + 37 = 0

and

{x^2} + {y^2} - 6y + 7 = 0

View answer and explanation

Correct option: C

x - y - 5 = 0

Option C (

x - y - 5 = 0

) is correct because it is the equation obtained by subtracting the equations of the two circles.

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