If $f\left( x \right) = \frac{1}{{x + 1}} - \log \left( {1 + x} \right),\;x > 0$, then $f$ is

both increasing and decreasing function

JEE MATHEMATICS MCQ: INCREASING & DECREASING

1 Medium

1 of 1

Analyzing +4 | -1

f\left( x \right) = \frac{1}{{x + 1}} - \log \left( {1 + x} \right),\;x > 0

, then

f

View answer and explanation

Correct option: B

a decreasing function

Option D (None of these) is correct because the maximum slope occurs at x = 5, which is at the boundary of the interval.

Practice All Chapter MCQs →

f\left( x \right) = \frac{{K\sin x + 2\cos x}}{{\sin x + \cos x}}

x

f\left( x \right) = {x^2} + ax + 1

a

f(x)=

\sin x-\cos x-a x+b

f(x)=x e^{x(1-x)}, x \in R

f

g

fog

f\left( x \right) = {x^3} + b{x^2} + cx + d

0 < {b^2} < c

\left( { - \infty ,\;\infty } \right)