JEE CHEMISTRY MCQ: 14 TH GROUP ELEMENTS (P-BLOCK)

Option D ($\mathrm{P}{\mathrm{b}_2}{\mathrm{O}_3}$) is correct because sesquioxide of lead is $\mathrm{P}{\mathrm{b}_2}{\mathrm{O}_3}$, which can also be written as $\mathrm{PbO} \cdot \mathrm{Pb}{\mathrm{O}_2}$.