JEE MATHEMATICS MCQ: HYPERBOLIC FUNCTIONS

1 Easy

1 of 1

Understanding +4 | -1

Which of the following functions is not defined at

x=0

View answer and explanation

Correct option: B

\operatorname{cosech} x

Option B (

\operatorname{cosech} x

) is correct because

\operatorname{cosech} x = \frac{1}{\sinh x}

and

\sinh x = 0

x=0

, making

\operatorname{cosech} x

undefined at

x=0

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