JEE MATHEMATICS MCQ: COMPOUND ANGLES

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Application +4 | -1

\sin \alpha+\sin \beta+\sin \gamma=0

and

\cos \alpha+

\cos \beta+\cos \gamma=0

, then value of

\cos (\alpha-\beta)+\cos (\beta-\gamma)+

\cos (\gamma-\alpha)

View answer and explanation

Correct option: A

-3 / 2

Option A (-3/2) is correct because the given conditions lead to

\cos(\alpha-\beta) = \cos(\beta-\gamma) = \cos(\gamma-\alpha) = -1/2

, and their sum is -3/2.

More Questions from COMPOUND ANGLES

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\tan \left( {A + B} \right) = p

\tan \left( {A - B} \right) = q

\tan \,\,2A

\cos \,\,x\,\,\cos \,\,y\,\,\sin \,\,\left( {x - y} \right) + \cos \,\,y\,\,\cos \,\,z\,\,\sin \,\,\left( {y - z} \right)

+ \cos \,\,z\,\,\cos \,\,x\,\,\sin \,\,\left( {z - x} \right) + \sin \,\,\left( {x - y} \right)\sin \,\,\left( {y - z} \right)\,\,\sin \,\,\left( {z - x} \right)

\sin \alpha, \cos \alpha

\sqrt{1+\sin \alpha \cos \alpha}

0<\alpha<\frac{\pi}{2}

\tan \,\,A = 2\,\,\tan \,\,B + \cot \,\,B,\;\;\mathrm{then}\;\,2\,\,\tan \left( {A - B} \right)\mathrm{\;}

A,B,C

{\tan ^2}\,\,\frac{A}{2} + {\tan ^2}\,\,\frac{B}{2} + {\tan ^2}\,\,\frac{C}{2}

A > 0,\,\;B > 0

A + B = \frac{\pi }{3}

\tan A\,\,\tan B