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JEE MATHEMATICS MCQ: STRAIGHT LINES

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ax+by−a2=0,  ax + by - {a^2} = 0,\; where a,ba,b are non-zero, is the equation to the straight line perpendicular to a line ll and passing through the point where ll crosses the x-axis. Then, equation to the line ll is
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Correct option: B
xa−yb=1\frac{x}{a} - \frac{y}{b} = 1
Option B (xa−yb=1\frac{x}{a} - \frac{y}{b} = 1) is correct because it represents the equation of the line ll that is perpendicular to the given line and passes through the x-intercept of the given line.

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