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JEE PHYSICS MCQ: UNITS & MEASUREMENTS
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If the value of the resistance is 10.845Ω and the value of the current is 3.23 A, then the potential difference is 35.02935 V. its value in correct significant figures would be
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Correct option: B
35.0 V
Option B (35.0 V) is correct because the result should be rounded to the least number of significant figures present in the given values, which is three.
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Reason: Acceleration has the dimensions of The method of dimensional analysis can be used to derive which of the following relations? Statement-I: Dimensions of constant of proportionality of constants can be derived from dimensional method
Statement-II: Numerical value of constant of proportionality can be found from experiments only The dimensions of torque are The physical quantity having the dimensions is A quantity X is given by , where is the permittivity of free space, L is a length, is a potential difference and is a time interval. The dimensional formula for X is the same as that of
