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JEE MATHEMATICS MCQ: PARABOLA

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The equation of the parabola whose vertex is (−1,−2)(-1,-2), axis is vertical, and which passes through the point (3,6)(3,6), is
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Correct option: A
x2+2x−2y−3=0x^2+2 x-2 y-3=0
Option A (x2+2x−2y−3=0x^2+2 x-2 y-3=0) is correct because substituting the vertex and the given point into the parabola equation yields this result.

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The equation of a common tangent to the parabolas y=x2y=x^2 and y=−(x−2)2y=-(x-2)^2 is A point PP moves such that slope of one tangent drawn from it to parabola y2=16xy^2=16 x is four times the slope of other tangent, then the length of latus rectum of the conic represented by locus of PP, is Let P,Q,RP,Q,R be three points on parabola y2=4x{y^2} = 4x and normal at PP and RR meet at QQ, then the locus of the mid-point of the chord PRPR is a parabola whose vertex is at The tangents at the end points of any chord through (1,0)(1,0) to the parabola y2+4x=8y^2+4 x=8 intersect The focus of the parabola x2=−16yx^2=-16 y is If II denotes the semi-latusrectum of the parabola y2=4ax{y^2} = 4ax and SPSP and SQSQ denote the segments of any focal chord PQ,SPQ,S being the focus, then SP,lSP,l and SQSQ are in the relation
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