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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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nth n^{\text {th }} term of the series 3⋅8+6⋅11+9⋅14+12⋅17+⋯3 \cdot 8+6 \cdot 11+9 \cdot 14+12 \cdot 17+\cdots will be
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Correct option: A
3n(3n+5)3 n(3 n+5)
Option A (3n(3n+5)3 n(3 n+5)) is correct because the nthn^{th} term of the series is the product of the nthn^{th} terms of the two sequences, which is 3n(3n+5)3n(3n+5).

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