NEET UG CHEMISTRY MCQ: THERMODYNAMICS

1 Medium

1 of 1

Understanding +4 | -1

A heat engine absorbs heat

{Q_1}

at temperature

{T_1}

and heat

{Q_2}

at temperature

\;{T_2}

, work done by the engine is (

{Q_1}

{Q_2}

) this data

View answer and explanation

Correct option: D

Does not violates 1st law of thermodynamics

Option D (Does not violates 1st law of thermodynamics) is correct because the first law of thermodynamics states that energy is conserved, and the work done by the engine can be equal to the sum of the heat absorbed.

More Questions from THERMODYNAMICS

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The internal energy of one mole of a gas is: An ideal gas is allowed to expand both reversibly and irreversibly in an isolated system. If

{T_i}

is the initial temperature and

{T_f}

is the final temperature, which of the following statements is correct? For which of the process, ∆S is negative? The work done by a weightless piston in causing an expansion ∆V (at constant temperature), when the opposing pressure, P is variable, is given by: Assertion :- At constant pressure of the change

\mathrm{H}_2 \mathrm{O}(\mathrm{s}) \rightarrow \mathrm{H}_2 \mathrm{O}(\mathrm{g})

work done is negative.

Reason :- During phase transition work done is always negative. For the reaction,

\mathrm{X}_2 \mathrm{O_4(l}) \longrightarrow 2 \mathrm{XO}_2(\mathrm{g}), \Delta U=2.1 \mathrm{~kcal}, \Delta S=20 \mathrm{~cal} \mathrm{~K}^{-1}

300 \mathrm{~K}

. Hence,

\Delta G