Skip to main content
Back to ELECTRO MAGNETIC INDUCTION

JEE PHYSICS MCQ: ELECTRO MAGNETIC INDUCTION

1 Medium
1 of 1
Application +4 | -1
The mutual inductance between two coils is 0.090.09 Henry. If the current in the primary coil changes from 0 to 20 A20 \mathrm{~A} in 0.006 s0.006 \mathrm{~s}, the e.m.f. induced in the secondary coil at that instant is
View answer and explanation
Correct option: D
300 V300 \mathrm{~V}
Option D (300 V300 \mathrm{~V}) is correct because it is the induced EMF calculated using the formula ε=MΔIΔt\varepsilon = M \frac{\Delta I}{\Delta t}.

More Questions from ELECTRO MAGNETIC INDUCTION

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.