A metal $'M'$ reacts with ${{\rm{N}}_2}$ to give a compound $'A'\left( {{M_3}N} \right).{\rm{ }}'A'$ on heating at high temperature gives back $'M'{\rm{and '}}A'$ on reacting with ${{\rm{H}}_2}{\rm{O}}$ gives a gas $B.{\rm{ }}'B'$ turns ${\rm{CuS}}{{\rm{O}}_4}$ solution blue on passing through it. $M{\rm{and}}B$ can be

NEET UG CHEMISTRY MCQ: S-BLOCK ELEMENTS

1 Hard

1 of 1

Analyzing +4 | -1

A metal

'M'

reacts with

{\mathrm{N}_2}

to give a compound

'A'\left( {{M_3}N} \right).\mathrm{ }'A'

on heating at high temperature gives back

'M'\mathrm{and '}A'

on reacting with

{\mathrm{H}_2}\mathrm{O}

gives a gas

B.\mathrm{ }'B'

turns

\mathrm{CuS}{\mathrm{O}_4}

solution blue on passing through it.

M\mathrm{and}B

can be

View answer and explanation

Correct option: B

\mathrm{Li and N}{\mathrm{H}_3}

Option B (

\mathrm{Li and N}{\mathrm{H}_3}

) is correct because Lithium reacts with nitrogen to form Lithium nitride (

\mathrm{L}{\mathrm{i}_3}\mathrm{N}

), which reacts with water to produce ammonia (

\mathrm{N}{\mathrm{H}_3}

), and ammonia turns

\mathrm{CuS}{\mathrm{O}_4}

solution blue.