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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

1 Easy
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Application +4 | -1
∑n=110tan⁡(tan⁡−1(2n−2))=\sum\limits_{{n=1}}^{10} \tan \left(\tan ^{-1}\left(2^n-2\right)\right)=
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Correct option: B
2026
Option B (2026) is correct because the sum can be simplified and calculated directly.

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