JEE MATHEMATICS MCQ: 2D GEOMETRY SYSTEM

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Analyzing +4 | -1

\alpha_1, \alpha_2, \alpha_3, \beta_1, \beta_2, \beta_3

are the values of

n

for which

\sum\limits_{r = 0}^{n - 1} {{x^{2r}}}

is divisible by

\sum\limits_{r = 0}^{n - 1} {{x^r}} ,

then the triangle having vertices

\left(\alpha_1, \beta_1\right),\left(\alpha_2, \beta_2\right)

and

\left(\alpha_3, \beta_3\right)

cannot be

View answer and explanation

Correct option: D

an equilateral triangle

Option D (an equilateral triangle) is correct because the vertices derived from the given condition do not form an equilateral triangle.

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