Skip to main content
Back to LIMITS

JEE MATHEMATICS MCQ: LIMITS

1 Easy
1 of 1
Analyzing +4 | -1
lim⁡x→0tan⁡x−sin⁡xx3=\lim _{x \rightarrow 0} \frac{\tan x-\sin x}{x^3}=
View answer and explanation
Correct option: B
12\frac{1}{2}
Option B (12\frac{1}{2}) is correct because after applying trigonometric identities and limit properties, the expression simplifies to 1/2.

More Questions from LIMITS

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.