If $ f(x)=3 x-5 $, then $ f^{-1}(x) $

Is given by $ \frac{1}{3 x-5} $

Does not exist because $ f $ is not one-one

Does not exist because $ f $ is not onto

JEE MATHEMATICS MCQ: FUNCTIONS

1 Easy

1 of 1

Application +4 | -1

f(x)=3 x-5

, then

f^{-1}(x)

View answer and explanation

Correct option: B

Is given by

\frac{x+5}{3}

Option B is correct because it represents the inverse function

f^{-1}(x)

obtained by solving for x in terms of y and swapping x and y.

Practice All Chapter MCQs →

f:(-\infty, 2] \longrightarrow(-\infty, 4]

f(x)=x(4-x)

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f(g(x))=(\sin \sqrt{x})^2

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f\left( x \right) = x - \left[ x \right]

{f^{ - 1}}\left( x \right)

f: R \rightarrow R

f(x)=x^4

f(x)=(x+1)^2-1(x \geq-1)

S=\left\{x: f(x)=f^{-1}(x)\right\}