In the organic compound $\mathop {C{H_3}}\limits^7 - \mathop {CH}\limits^6 = \mathop {CH}\limits^5 - \mathop {\mathop C\limits_{\begin{array}{*{20}{c}} {||} \\ O \end{array}} }\limits^4 - \mathop C\limits^3 {H_2} - \mathop C\limits^2 = \mathop {CH}\limits^1$ the state of hybridization of carbons 2, 4 and 6 are in the following sequence

JEE CHEMISTRY MCQ: CHEMICAL BONDING & MOLECULAR STRUCTURE

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Understanding +4 | -1

In the organic compound

\mathop {C{H_3}}\limits^7 - \mathop {CH}\limits^6 = \mathop {CH}\limits^5 - \mathop {\mathop C\limits_{\begin{array}{cccccccccccccccccccc} {||} \\ O \end{array}} }\limits^4 - \mathop C\limits^3 {H_2} - \mathop C\limits^2 = \mathop {CH}\limits^1

the state of hybridization of carbons 2, 4 and 6 are in the following sequence

View answer and explanation

Correct option: B

s p, s p^2, s p^2

The correct answer is

s p, s p^2, s p^2

because carbon 2 is sp hybridized, carbon 4 is sp2 hybridized, and carbon 6 is sp2 hybridized.