JEE MATHEMATICS MCQ: PERMUTATIONS

1 Easy

1 of 1

Application +4 | -1

In a circus there are ten cages for accommodating ten animals. Out of these four cages are so small that five out of 10 animals cannot enter into them. In how many ways will it be possible to accommodate ten animals in these ten cages?

View answer and explanation

Correct option: B

86400

Option B (86400) is correct because it first arranges the animals that can't go into the small cages, then arranges the remaining animals in the remaining cages.

More Questions from PERMUTATIONS

Practice All Chapter MCQs →

How many different nine digit numbers can be formed from the number 223355888 by rearranging its digits so that the odd digits occupy even positions? The number of ways in which

r

letters can be posted in

n

letterboxes in a town is The number of four-digit numbers that can be made with the digits

1,2,3,4

and 5 in which atleast two digits are identical, is The number of ways in which a pack of 52 cards can be divided equally into four groups, is Five digited numbers with distinct digits are formed by using the digits, 5, 4, 3, 2, 1, 0. The number of those numbers which are multiples of 3, is A man invites a party to

\left( {m + n} \right)

friends to dinner and places m at one round table and

n

at another. The number of ways of arranging the guests is