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JEE MATHEMATICS MCQ: RATE MEASURE

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A particle moves in a straight line so that

s = \sqrt t

,then its acceleration is proportional to

View answer and explanation

Correct option: A

{\left( {\mathrm{velocity}} \right)^3}

Option C (

\frac{2}{{\sqrt 5 }}

) is correct because it is the perpendicular distance from the origin to the normal of the curve at x=0.

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The surface area of a sphere when its volume is increasing at the same rate as its radius, is A particle is moving in a straight line has velocity and displacement equation as

v = 4\sqrt {1 + s}

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m

. The initial velocity of the particle is The diagonal of a square is changing at the rate of 0.5 cm

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c{m^2}

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cubic meters of helium gas. If a leak in the balloon causes the gas to escape at the rate of

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\frac{1}{2 \pi+16}

\mathrm{cm} / \mathrm{sec}

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