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JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

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Application +4 | -1
 △ABC\triangle A B C is such that sin⁡(2A+B)=12\sin (2 A+B)=\frac{1}{2}.
If A,BA, B and CC are in AP, then the values of A,BA, B and CC are
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Correct option: A
π4,π3,5π12\frac{\pi}{4}, \frac{\pi}{3}, \frac{5 \pi}{12}
Option A (π4,π3,5π12\frac{\pi}{4}, \frac{\pi}{3}, \frac{5 \pi}{12}) is correct because by using the given condition and the properties of an arithmetic progression, we can find the values of A, B, and C.

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