NEET UG PHYSICS MCQ: GRAVITATION

1 Hard

1 of 1

Application +4 | -1

An astronaut takes a ball of mass

m

from earth to space. He throws the ball into a circular orbit about earth at an altitude of

318.5 \mathrm{~km}

. From earth's surface to the orbit, the change in total mechanical energy of the ball is

x \frac{G M_e m}{21 R_e}

. The value of

x

is (take

\left.{R}_{{e}}=6370 \mathrm{~km}\right)

View answer and explanation

Correct option: A

Option A (11) is correct because the change in total mechanical energy is calculated by considering the change in potential and kinetic energy from the Earth's surface to the orbit.

More Questions from GRAVITATION

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If a particle of mass m is moving in a horizontal circle of radius r with a centripetal force

\left( { - K/{r^2}} \right)

the total energy is Suppose the law of gravitational attraction suddenly changes and becomes an inverse cube law i.e.

F \propto \frac{1}{r^3}

, but still remaining a central force. Then Two satellites A and B go round a planet P is circular orbits having radii 16 R and 2 R respectively. If the speed of satellite A is

6\,m{s^{ - 1}}

the speed of the satellite B will be [in m/s] nearly The total energy of satellite moving with an orbital velocity

v

around the earth is Two satellites of same mass are launched in the same orbit of radius

r

around the earth so as to rotate opposite to each other. If they collide inelastically and stick together as wreckage, the total energy of the system just after collision is Statement-1: There is almost no effect of rotation of earth at poles.
Statement-2: Because rotation of earth is about polar axis.