JEE MATHEMATICS MCQ: RATE MEASURE

1 Easy

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Application +4 | -1

The rate of growth of bacteria in a culture is proportional to the number of bacteria present and the bacteria count is 1000 at initial time

t = 0

. The number of bacteria is increased by 20% in

2\,h

. If the population of bacteria is 2000 after

\frac{k}{{{{\log }_e}(6/5)}}h

, then

{\left( {\frac{k}{{{{\log }_e}2}}} \right)^2}

is equal to

View answer and explanation

Correct option: A

Option A (4) is correct because after solving the differential equation for bacterial growth and substituting the given conditions, the value of the expression is found to be 4.

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