JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

1 Easy

1 of 1

Application +4 | -1

\cos ^2 \frac{3 \pi}{5}+\cos ^2 \frac{4 \pi}{5}

is equal to

View answer and explanation

Correct option: D

\frac{3}{4}

Option D (

\frac{3}{4}

) is correct because using the trigonometric identities and values, the expression simplifies to

\frac{3}{4}

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\left[ {0,\;\,\frac{\pi }{2}} \right]

\left( {x,\,y} \right)

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\left( {\sqrt {{{\sin }^2} - \sin \,\,x + \frac{1}{2}} } \right){2^{{{\sec }^2}y}}\,\, \cdot \,\, \le 1

\mathrm{X}

\theta \rightarrow \frac{\pi}{2}

\sin x+\cos x=\frac{\sqrt{7}}{2}

x \in\left[0, \frac{\pi}{4}\right]

\tan \frac{x}{2}

\tan \frac{\pi}{5}+2 \tan \frac{2 \pi}{5}+4 \cot \frac{4 \pi}{5}

0 < x < \pi

\cos x+\sin x=\frac{1}{2}

\tan x