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NEET UG PHYSICS MCQ: THERMODYNAMICS

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One mole of an ideal mono atomic gas is compressed isothermally in a rigid vessel to double its pressure at room temperature, 270C{27^0}C. The work done on the gas will be
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Correct option: D
300 R ln 2
Option D (300 R ln 2) is correct because the work done in an isothermal process is given by W=−nRTln⁡(V2V1)W = -nRT \ln(\frac{{V_2}}{{V_1}}) and since the pressure doubles, the volume halves.

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