Identify the correct order of acidic strength of ${\rm{C}}{{\rm{O}}_2},{\rm{CuO}},{\rm{CaO}},{{\rm{H}}_2}{\rm{O}}:$

${\rm{CaO}} < CuO < {{\rm{H}}_2}{\rm{O}} < C{{\rm{O}}_2}$

${{\rm{H}}_2}{\rm{O}} < CuO < CaO < {{\rm{H}}_2}{\rm{O}}$

${\rm{CaO}} < {{\rm{H}}_2}{\rm{O}} < CuO < C{{\rm{O}}_2}$

${{\rm{H}}_2}{\rm{O}} < C{{\rm{O}}_2} < CaO < CuO$

JEE CHEMISTRY MCQ: Equilibrium

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Understanding +4 | -1

Identify the correct order of acidic strength of

\mathrm{C}{\mathrm{O}_2},\mathrm{CuO},\mathrm{CaO},{\mathrm{H}_2}\mathrm{O}:

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Correct option: A

\mathrm{CaO} < CuO < {\mathrm{H}_2}\mathrm{O} < C{\mathrm{O}_2}

Option A (

\mathrm{CaO} < CuO < {\mathrm{H}_2}\mathrm{O} < C{\mathrm{O}_2}

) is correct because metal oxides are generally basic, non-metal oxides are acidic, and CaO is more basic than CuO.

Practice All Chapter MCQs →

\mathrm{K}_1

\mathrm{K}_2

\mathrm{N}_2(\mathrm{~g})+\mathrm{O}_2(\mathrm{~g}) \rightleftharpoons 2 \mathrm{NO}(\mathrm{g})\quad\ldots

\mathrm{NO}(\mathrm{g}) \rightleftharpoons \frac{1}{2} \mathrm{~N}_2(\mathrm{~g})+\frac{1}{2} \mathrm{O}_2(\mathrm{~g})\quad\ldots

K{a_1},\,\,\,K{a_2}\,\,\,\mathrm{and}\,\,\,K{a_3}

\begin{array}{l} {H_2}S\leftrightharpoons{H^ + } + H{S^ - }\\ H{S^ - }\leftrightharpoons{H^ + } + {S^{2 - }}\\ {H_2}S\leftrightharpoons2{H^ + } + {S^{2 - }} \end{array}

K{a_1},\,\,K{a_2}\,,K{a_3}

\mathrm{pH}

0.1 \mathrm{~M}-\mathrm{N}_2 \mathrm{H}_4

\mathrm{N}_2 \mathrm{H}_4,

K_{{b}_1}=3.6 \times 10^{-6}, K_{{b}_2}=6.4 \times 10^{-12}, \log 2=0.3

\log 3=0.48

{\text{Ba}}{{\text{O}}_2}(s) \rightleftharpoons {\text{BaO}}(s) + {{\text{O}}_2}(g);\Delta H = - {\text{ve}}.

\text{O}_2