Question

Leaching of gold with dilute aqueous solution of $NaCN$ in presence of oxygen gives complex [A], which on reaction with zinc forms the elemental gold and another complex [B]. [A] and [B], respectively are:

Accepted Answer

${\left[ {Au{{(CN)}_2}} ight]^ - }\,\,{	ext{and}}\,\,{\left[ {Zn{{(CN)}_4}} ight]^{2 - }}$

Answer

${\left[ {Au{{(CN)}_4}} ight]^ - }\,\,{	ext{and}}\,\,{\left[ {Zn{{(CN)}_2}{{(OH)}_2}} ight]^{2 - }}$

Answer

${\left[ {Au{{(CN)}_2}} ight]^ - }\,\,{	ext{and}}\,\,\,{\left[ {Zn{{(OH)}_4}} ight]^{2 - }}$

Answer

${\left[ {Au{{(CN)}_4}} ight]^{2 - }}\,{	ext{and}}\,\,\,{\left[ {Zn{{(CN)}_6}} ight]^{4 - }}$

JEE CHEMISTRY MCQ: GENERAL PRINCIPLES AND PROCESSES OF ISOLATION OF ELEMENTS

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