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NEET UG CHEMISTRY MCQ: CLASSIFICATION OF ELEMENTS AND PERIODICITY IN PROPERTIES

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The amount of energy released when 10610^6 atoms of iodine in vapour state are converted to I−\mathrm{I}^{-}ions is 4.9×10−13 J4.9 \times 10^{-13} \mathrm{~J}. What is the electron affinity of iodine in eV\mathrm{eV} per atom?
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Correct option: D
-3.06
Option D (-3.06) is correct because the electron affinity is calculated by dividing the total energy released by the number of atoms and converting the units to eV.

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