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NEET UG PHYSICS MCQ: ELECTRIC POTENTIAL AND CAPACITANCE

1 Easy
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Understanding +4 | -1
A spherical equipotential surface is not possible
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Correct option: B
For a dipole
Option B (For a dipole) is correct because the equipotential surfaces for a dipole are complex and not spherical.

More Questions from ELECTRIC POTENTIAL AND CAPACITANCE

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A parallel plate capacitor is filled with a dielectric whose dimensions are the same as that of the capacitor. The capacitor is connected to a battery.
Statement 1: If the dielectric is pulled out, the electric field inside the capacitor increases.
Statement 2: The electric field inside the dielectric is lesser than the electric field in the region outside the dielectric.
Statement-1: A parallel plate capacitor is charged to a potential difference of 100Β V100 \mathrm{~V}, and disconnected from the voltage source. A slab of dielectric is then slowly inserted between the plates. Compared to the energy before the slab was inserted, the energy stored in the capacitor with the dielectric is decreased.
Statement-2: When we insert a dielectric between the plates of a capacitor, the induced charges tend to draw in the dielectric into the field (just as neutral objects are attracted by charged objects due to induction). We resist this force while slowly inserting the dielectric, and thus do negative work on the system, removing electrostatic energy from the system.
An electric dipole of moment pβƒ—{\vec p} placed in a uniform electric field Eβƒ—{\vec E} has minimum potential energy when the angle between pβƒ—{\vec p} and Eβƒ—{\vec E} is A capacitor has air as dielectric medium and two conducting plates of area 12Β cm212 \mathrm{~cm}^2 and they are 0.6Β cm0.6 \mathrm{~cm} apart. When a slab of dielectric having area 12Β cm212 \mathrm{~cm}^2 and 0.6Β cm0.6 \mathrm{~cm} thickness is inserted between the plates, one of the conducting plates has to be moved by 0.2Β cm0.2 \mathrm{~cm} to keep the capacitance same as in previous case. The dielectric constant of the slab is: (GivenΒ Ξ΅0=8.834Γ—10βˆ’12Β F/m)\left(\text{Given }\varepsilon_0=8.834 \times 10^{-12} \mathrm{~F} / \mathrm{m}\right) Assertion:- Two adjacent conductors carrying the same charge can be at different potentials.
Reason:- The conductors may have different sizes and hence different capacitances.
The electric field between the plates of a parallel plate capacitor when connected to a certain battery is E0.{E_0}. If the space between the plates of the capacitor is filled by introducing a material of dielectric constant KK without disturbing the battery connections, the field between the plates shall be
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