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JEE CHEMISTRY MCQ: ALDEHYDES & KETONES & CARBOXYLIC ACIDS

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Acetone on reduction gives:
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Correct option: D
(CH3)2CHOH{\left( {\mathrm{C}{\mathrm{H}_3}} \right)_2}\mathrm{CHOH}
Option D ((CH3)2CHOH{\left( {\mathrm{C}{\mathrm{H}_3}} \right)_2}\mathrm{CHOH}) is correct because the reduction of acetone (a ketone) results in the formation of isopropyl alcohol (2-propanol), which has the structure (CH3)2CHOH{\left( {\mathrm{C}{\mathrm{H}_3}} \right)_2}\mathrm{CHOH}.

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