NEET UG PHYSICS MCQ: GRAVITATION

1 Easy

1 of 1

Application +4 | -1

A particle of mass

10 \mathrm{~g}

is kept on the surface of a uniform sphere of mass

100 \mathrm{~kg}

and radius

10 \mathrm{~cm}

. Find the work to be done against the gravitational force between them to take the particle far away from the sphere. (you may take

\mathrm{G}=6.67 \times 10^{-11} \mathrm{Nm}^2 / \mathrm{kg}^2

)

View answer and explanation

Correct option: B

6.67 \times 10^{-10} \mathrm{~J}

Option B (

6.67 \times 10^{-10} \mathrm{~J}

) is correct because the work done is equal to the change in potential energy, which can be calculated using the gravitational constant, masses, and radius.

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If a particle of mass m is moving in a horizontal circle of radius r with a centripetal force

\left( { - K/{r^2}} \right)

the total energy is Suppose the law of gravitational attraction suddenly changes and becomes an inverse cube law i.e.

F \propto \frac{1}{r^3}

, but still remaining a central force. Then Two satellites A and B go round a planet P is circular orbits having radii 16 R and 2 R respectively. If the speed of satellite A is

6\,m{s^{ - 1}}

the speed of the satellite B will be [in m/s] nearly The total energy of satellite moving with an orbital velocity

v

around the earth is Two satellites of same mass are launched in the same orbit of radius

r

around the earth so as to rotate opposite to each other. If they collide inelastically and stick together as wreckage, the total energy of the system just after collision is Statement-1: There is almost no effect of rotation of earth at poles.
Statement-2: Because rotation of earth is about polar axis.