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NEET UG PHYSICS MCQ: DUAL NATURE OF RADIATION AND MATTER

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Application +4 | -1
An electron (mass m) with an initial velocity v=v0i^v = {v_0}\hat i is in an electric field E=E0j^E = {E_0}\hat j . If initial wavelength λ0=h/mv0{\lambda _0} = h/m{v_0} , then its de Broglie wavelength at time t is given by
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Correct option: C
λ01+e2E02t2m2v02\frac{{{\lambda _0}}}{{\sqrt {1 + \frac{{{e^2}E_0^2{t^2}}}{{{m^2}v_0^2}}} }}
Option C is correct because the de Broglie wavelength changes with the electron's velocity, which is affected by the electric field.

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