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JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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Application +4 | -1
The tangent of the curve y=f(x)y = f\left( x \right) at the point with abscissa x=1x = 1 form an angle of π/6\pi /6 and at the point x=2x = 2 an angle of π/3\pi /3 and at the point x=3x = 3 an angle of π/4\pi /4. If f′′(x)f''\left( x \right) is continuous, then the value of
∫  13f′′(x)f′(x)  dx+∫ 23f′′(x)  dx\mathop {\int \,\,}\limits_1^3 f''\left( x \right)f'\left( x \right)\,\,dx + \mathop {\int \,}\limits_2^3 f''\left( x \right)\,\,dx, is
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Correct option: C
4−3  33\frac{{4 - 3\,\,\sqrt 3 }}{3}
Option C is correct because the expression simplifies to 4−3  33\frac{{4 - 3\,\,\sqrt 3 }}{3} after evaluating the integrals using the given information about the derivatives.

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