Given ${\rm{\vec c}} = {\rm{\vec a}} \times {\rm{\vec b}}$. The angle which ${\rm{\vec a}}$ makes with ${\rm{\vec c}}$ is

NEET UG PHYSICS MCQ: MOTION IN PLANE

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Understanding +4 | -1

Given

\mathrm{\vec c} = \mathrm{\vec a} \times \mathrm{\vec b}

. The angle which

\mathrm{\vec a}

makes with

\mathrm{\vec c}

View answer and explanation

Correct option: C

{90^0}

Given

\mathrm{\vec c} = \mathrm{\vec a} \times \mathrm{\vec b}

, the angle which

\mathrm{\vec a}

makes with

\mathrm{\vec c}

{90^0}

because the cross product results in a vector perpendicular to both original vectors.

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\mathrm{\vec a}\,and\,\mathrm{\vec b}

\mathrm{\vec a}\,and\,\mathrm{\vec b}

\overrightarrow P \,\,.\,\,\overrightarrow Q = 0\,and\,\overrightarrow P \,\, \times \,\,\overrightarrow Q = 0

\overrightarrow Q \,and\,\overrightarrow R

\vec{A}=3 \hat{i}+4 \hat{j}

\vec{B}=6 \hat{i}+8 \hat{j}

A

B

\overrightarrow{\mathrm{A}}

\overrightarrow{\mathrm{B}}

{\cot ^{ - 1}}\left( 2 \right)