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JEE PHYSICS MCQ: ELECTRIC FIELDS AND CHARGES

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Analyzing +4 | -1

Consider

\overrightarrow {{E_1}} = x\hat i + \hat j

and

\overrightarrow {{E_2}} = x{y^2}\hat i + {x^2}y\;\hat j;

then

View answer and explanation

Correct option: C

Both are electrostatic

Option C (Both are electrostatic) is correct because for an electrostatic field,

\nabla \times \vec{E} = 0

, and both given fields satisfy this condition.

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